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Urlopen Error Socket Create_connection Returns An Empty List

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Reload to refresh your session. python share|improve this question edited Mar 3 '15 at 14:28 Braiam 3,26882656 asked Feb 26 '15 at 20:31 oridm 8812 Does this post answer your question? –sharshofski Feb 26 Please try the request again. If specified, `local_hostname` is used as the FQDN of the local host. check over here

Example 1 From project play1, under directory python/Lib, in source file telnetlib.py. on remote/virtual systems Next message: [Mne_analysis] error downloading sample data set Messages sorted by: [ date ] [ thread ] [ subject ] [ author ] More information about the Mne_analysis Personal Open source Business Explore Sign up Sign in Pricing Blog Support Search GitHub This repository Watch 2 Star 7 Fork 4 arlolra/flashproxy Code Issues 0 Pull requests 0 Projects fqdn = socket.getfqdn() if '.' in fqdn: self.local_hostname = fqdn else: # We can't find an fqdn hostname, so use a domain literal addr = '127.0.0.1' try: addr = socket.gethostbyname(socket.gethostname()) except

Python Smtplib Error Handling

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  • Update As per information about empty proxy list, I would suggest using an urlopener, with the proxy name and information.
  • Here's the exact error: Traceback (most recent call last): File "", line 1, in b = urllib.urlopen('http://www.google.com') File "C:\Python26\lib\urllib.py", line 87, in urlopen return opener.open(url) File "C:\Python26\lib\urllib.py", line 203, in
  • Try to strip your code a little, leaving an MVE.

In my system the proxy configuration is through a .PAC file. The final version is below. This worked fine... hope that helps... –Steve Hall Nov 27 '14 at 10:45 So it doesn't get catched even with the second except statement, which is supposed to catch everything...

Score: 10 def __init__(self, host=None, port=0, timeout=socket._GLOBAL_DEFAULT_TIMEOUT): """Constructor. Smtplib Sendmail I also tried using urllib2 to send a request to Google but it took time and timed out too. By default, smtplib.SMTP_PORT is used. What object can prove the equations?

Is there a better way to do it? If specified, `local_hostname` is used as the FQDN of the local host. Joran has a great answer, it definitely works. If *source_address* is set it must be a tuple of (host, port) for the socket to bind as a source address before making the connection.

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Is there a workaround? Every polynomial with real coefficients is the sum of cubes of three polynomials How to apply for UK visit visa after four refusals? Python Smtplib Error Handling Score: 10 def __init__(self, host, port=None, strict=None, timeout=socket._GLOBAL_DEFAULT_TIMEOUT): self.timeout = timeout self.sock = None self._buffer = [] self.__response = None self.__state = _CS_IDLE self._method = None self._tunnel_host = None self._tunnel_port = Send Email Python Camille Rozier -------------- next part -------------- An HTML attachment was scrubbed...

current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. check my blog If specified, `host' is the name of the remote host to which to connect. They are extracted from open source Python projects. So i opended that file, took out the default proxy url, for me it was http://168.219.61.250:8080/ Following test code worked for me : import urllib2 proxy_support = urllib2.ProxyHandler({'http': 'http://168.219.61.250:8080/'}) opener =

Java Program Creek Python socket._GLOBAL_DEFAULT_TIMEOUT Examples The following are 33 code examples for showing how to use socket._GLOBAL_DEFAULT_TIMEOUT. Score: 10 def __init__(self, host='', port=0, local_hostname=None, timeout=socket._GLOBAL_DEFAULT_TIMEOUT): """Initialize a new instance. By default, smtplib.SMTP_PORT is used. http://crimsonskysoftware.com/urlopen-error/urlopen-error-10061-connection.html Score: 10 def __init__(self, host, port=None, strict=None, timeout=socket._GLOBAL_DEFAULT_TIMEOUT, source_address=None): self.timeout = timeout self.source_address = source_address self.sock = None self._buffer = [] self.__response = None self.__state = _CS_IDLE self._method = None self._tunnel_host

Oh, and I also had to add "socket" to my list of imports. share|improve this answer answered Jul 3 '09 at 2:53 mhawke 40.1k53350 1 I'm getting this error when I try that: IOError: [Errno socket error] [Errno 10060] A connection attempt failed Name for the peak of a plateau Modify functions in R using body, formals and environment methods Puzzler - which spacecraft(s) (actually) incorporated wooden structural elements?

Without this I could understand the except not handling correctly - but I don't understand why it wasn't firing at all, or even generating a "not defined" error....

Your cache administrator is webmaster. Score: 10 def __init__(self, host=None, port=0, timeout=socket._GLOBAL_DEFAULT_TIMEOUT): """Constructor. Score: 10 def __init__(self, host='', port=0, local_hostname=None, timeout=socket._GLOBAL_DEFAULT_TIMEOUT): """Initialize a new instance. Given a limit with notation f, how would you solve?

Human vs. Development of retrosynthesis plan How do really talented people in academia think about people who are less capable than them? Why does my capsule collider fall without my object (Unity)? http://crimsonskysoftware.com/urlopen-error/urlopen-error-60.html Strange device identification TNG Season 5 Episode 15 - Is the O'Brien newborn child possessed, and is this event ever revisited/resolved/debunked?

If specified, `host' is the name of the remote host to which to connect. As I said, I tried to catch the exception exactly in the same way as you, and it worked for me. –Andrey Sobolev Nov 27 '14 at 10:59 | show 1 Another approach is: def checkNet(): import requests try: response = requests.get("http://www.google.com") print "response code: " + response.status_code except requests.ConnectionError: print "Could not connect" The benefit is you can use the response more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed

share|improve this answer edited Jul 20 '09 at 9:31 answered Jul 20 '09 at 9:25 fizzbuzz 1,70031331 2 Where did you find your proxy config? –mandroid Jul 20 '09 at Is there a safe way to get around this?