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Urlopen Error No Host Given

Browse other questions tagged python urllib or ask your own question. Many thanks all, I hope this helps someone out at some point. Not the answer you're looking for? To emailaddress: To name: From name: Extra information in the email body (optional): Email: I am sending you the codedump of urllib.error.URLError: python 3 that you check over here

What was the first operating system to feature a separate kernel? here is the code I have that is not working.... This is also unnecessary; mystring is already a string, so 'http://www.myurl.com/' + mystring would suffice. more hot questions question feed lang-py about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation

Reload to refresh your session. Does the reciprocal of a probability represent anything? Thanks, I am sure that is the case and I'll look into using shutil, but the line that is throwing errors is bolded below, so I have not been able to What is way to eat rice with hands in front of westerners such that it doesn't appear to be yucky?

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  7. It works if I just call urlopen in the interpreter, or if I call the entire function that makes the url, but it doesn't work when I call it in a
  8. I use urllib and elementTree to parse the xml.
  9. Code: def TivoDL(address, mak, link): pm = urllib2.HTTPDigestAuthHandler() pm.add_password('TiVo DVR', address, 'tivo', mak) opener = urllib2.build_opener(pm) download=opener.open(link) f=open(some_path, "w") f.write(download) f.close() anyway thanks for your help, and if anyone sees what

Here is the sequence of function calls leading up to the error, in the order they occurred. /home/gsnedders/gsnedders.html5.org/outliner/process.py in () 77prints.render(walker(treeToc),encoding="utf-8") 78 79 80if__name__=="__main__": =>81main() main= /home/gsnedders/gsnedders.html5.org/outliner/process.py in main() I don't really want to give away the real url.. Adv Reply December 9th, 2008 #7 troutbum13 View Profile View Forum Posts Private Message Just Give Me the Beans! I have edited my code to hopefully give a clearer picture.

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. They are all search Google Blog Search with different queries. Do you want to help us debug the posting issues ? < is the place to report it, thanks !

Could in any > case urllib() be sensitive to the content of the requested URL (full of "&" > chars) ? > > Thank you for any help. > Patrick: Maybe Why are only passwords hashed? Why were Navajo code talkers used during WW2? As you can tell I am new at this Adv Reply October 29th, 2008 #2 ghostdog74 View Profile View Forum Posts Private Message I Ubuntu, Therefore, I Am Join Date

import urllib2 req = urllib2.Request(url='http://stackoverflow.com/') f = urllib2.urlopen(req) print f.read() share|improve this answer answered Apr 20 '10 at 3:36 community wiki Eddy Pronk 3 Good idea but no luck, I Could you help me please ? creating a symbolic link in linux directory Is there a developers image of 16.04 LTS? Join them; it only takes a minute: Sign up urllib2 error no host given up vote 0 down vote favorite EDIT:(SOLVED) When I am reading the values in from my file

The file which I'm getting the values for mystring from has \n at the end of every line when i'm reading it in. http://crimsonskysoftware.com/urlopen-error/urllib2-urlerror-urlopen-error-errno-65-no-route-to-host.html What does 彼女は私ほど自分のことを好きじゃない mean? There are certain contexts where that kind of thing works in Python, but this isn't one of them. How could a language that uses a single word extremely often sustain itself?

The values for mystring were read in from a file. User contributions on this site are licensed under the Creative Commons Attribution Share Alike 4.0 International License. Many thanks. –Paul Tricklebank Feb 1 '13 at 15:37 oops. this content Anyway here is how I got it working.

after the loop has run a few times str(mystring) changes to give a different set of results. Remove the redundant urlopen() call: lecture = urllib.request.urlopen("http://www.wdyl.com/profanity?q="+text_to_check) output = lecture.read() You may have a broken proxy configuration; verify that your proxies are sane by inspecting what Python finds in the It would be better to decode it into ascii format: with urllib.request.urlopen("http://www.wdyl.com/profanity?q=" + urllib.parse.quote(text_to_check)) as response: output = response.read() output = output.decode('ascii') print (output) share|improve this answer answered Jul 14 '15

The time now is 07:53 AM.

Your url is incorrect : replace \ with /. –Dan Cornilescu Dec 30 '15 at 21:00 As simple an error as this may be, I can easily envision a I have this small code: import urllib.request x = urllib.request.urlopen('https:\\www.google.com') print(x.read()) When I run it Python shouts out this error: Traceback (most recent call last): File "C:/Users/The Kids/Desktop/urllib.py", line 3, in all are pretty uniform in that they are single words. Myurl.com/mystring/otherstuff/page_counter/morestuff.htm The /n being read from the file spliced my url and gave urllib problems...... [1] I use windows.

Hot Network Questions Using DC in transformers? Code: Traceback (most recent call last): File "testing.py", line 33, in if __name__ == '__main__': TivoDL('192.168.0.16', '123456789', 'http://192.168.0.16:80/download/Nature.TiVo?Container=%2FNowPlaying&id=1224369') File "testing.py", line 28, in TivoDL download=opener.open(link) File "/usr/lib/python2.5/urllib2.py", line 387, in asked 3 years ago viewed 6933 times active 11 months ago Get the weekly newsletter! have a peek at these guys Change the URL and it should work.

You cannot pass that to urlopen() again. make sure its an actual ip number. Does the reciprocal of a probability represent anything? This is splitting my request string at that point. –Paul Tricklebank Feb 1 '13 at 15:51 1 The next step is to accept your own answer. :)) –Markus Unterwaditzer Feb

Die Liebe höret nimmer auf What do you call someone without a nationality? Join them; it only takes a minute: Sign up urllib.request error!! typically I would just use: Code: import urllib ElementTree as ET feed_url = urllib.urlopen('http://MyRssFeed') tv_tree = ET.parse(feed_url) tv_root = tv_tree.getroot() tv_iter = tv_root.getiterator('SomeElement') ... Browse other questions tagged python string urllib2 or ask your own question.

There are certain contexts where that kind of thing works in Python, but this isn't one of them -- you'd need something like "f.write(download.read())" instead.