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Urllib2.httperror Http Error 403 Forbidden Wikipedia

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Retrieved January 11, 2016. ^ Fielding, R.; Reschke, J. (June 2014). "401 Unauthorized". Best way to repair rotted fuel line? wireshark showed that only the User-Agent was sent, along with Connection: close, Host: www.nseindia.com, Accept-Encoding: identity Andrean, thank you very much, it solved the issue, unfortunate and funny that I tried asked 3 years ago viewed 46407 times active 2 years ago Linked 2 urllib2.URLError: 1 What causes “urlopen error [Errno 13] check over here

still there are many other reasons why a server might return a 403, check out the other answers on the topic as well. How do we play with irregular attendance? You will need to consult the owners of the site, as to what should be the names of the parameters you pass in your GET request, so that you may access Connect to Services Connect to personal services for more relevant search results across services.

Urllib2.httperror Http Error 403 Forbidden Python

This doesn't apply to the original question, of course, but it's still useful to know. –efotinis Jul 28 '13 at 9:19 add a comment| Your Answer draft saved draft discarded I think this should definitely be posted along with setting the User-Agent as a solution to the 403 error; This happened to me on numerous sites (I think most of them contact | privacy policy | terms of use © 2014-15 recalll × Modal header Body... Describing a shrine, just not a Shinto shrine?

  1. What are the alternatives of compound interest for a Muslim?
  2. After the authentication I'm calling url by url = "api.twitter.com/1.1/search/show.json?id="+tweetid and then tweetdata=urllib2.urlopen(url).read() Could you please help me figure out why?
  3. Check this Out Similar queries python - urllib2.HTTPError: HTTP Error 403: Forbidden - Stack Overflow python - urllib2.HTTPError: HTTP Error 403: Forbidden - Stack Overflow python urllib2.HTTPError: HTTP Error 403: Forbidden
  4. I have this problem with import re from urllib2 import urlopen string='http://www.google.com/search?num=20&hl=en&q=ipod&btnG=Search' file_source=file("google_source.txt",'w') file_source.write(urlopen(string).read()) page_content=file_source.readlines() Traceback (most recent call last) : File "C:/Python25/google.py", line 5,in file_source.write(urlopen(string).read()) File "C:\Python25\lib\urllib2.py", line 124
  5. See also[edit] Internet portal .htaccess List of HTTP status codes URL redirection References[edit] ^ "HTTP Extensions for Web Distributed Authoring jand Versioning (WebDAV)".

Why is the FBI making such a big deal out Hillary Clinton's private email server? Now with your help, the code itself works but I still get bad authentication data: code 215 error.. Many thanks. –MaiTiano Mar 6 '12 at 1:52 It's totally ridiculous that they also block HEAD request which are useful e.g. Urllib2 User Agent share|improve this answer answered Nov 29 '13 at 6:51 Games Brainiac 27.1k1672124 how can i add username and password? –Anand Nov 29 '13 at 6:53 @Anand I'm

In lightning component, are only html items responsive at all? python - urllib2.HTTPError: HTTP Error 403: Forbidden - Stack Overflow View More at http://stackoverflow.com/questions/13303449/urllib2-httperror-htt... TNG Season 5 Episode 15 - Is the O'Brien newborn child possessed, and is this event ever revisited/resolved/debunked? more hot questions question feed lang-py about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation

View More at http://stackoverflow.com/questions/5632351/urllib2-httperror-http... Python Urllib Headers The operation is forbidden to all users. class AppAuthHandler(tweepy.auth.AuthHandler): TOKEN_URL='https://api.twitter.com/oauth2/token' def __init__(self,consumer_key,consumer_secret): token_credential = '{}:{}'.format(*map(urllib.quote, [consumer_key, consumer_secret])) credential = base64.b64encode(token_credential) value = {'grant_type': 'client_credentials'} data = urllib.urlencode(value) req = urllib2.Request(self.TOKEN_URL) req.add_header('Authorization', 'Basic {}'.format(credential)) req.add_header('Content-Type', 'application/x-www-form-urlencoded;charset=UTF-8') response=urllib2.urlopen(req, data) json_response=json.loads(response.read()) Is Certificate validation done completely local?

Python Requests 403 Forbidden

current community chat Stack Overflow Meta Stack Overflow your communities Sign up or log in to customize your list. Next message: [Tutor] Error 403 when accessing wikipedia articles? Urllib2.httperror Http Error 403 Forbidden Python IETF. Python Requests 403 Error In it, you'll get: The week's top questions and answers Important community announcements Questions that need answers see an example newsletter By subscribing, you agree to the privacy policy and terms

Former boss asking me to do presentations What would have happened to the world if the sepoy mutiny of 1857 had suceeded? check my blog Integer function which takes every value infinitely often Why is C# Dim a Chord in B Minor? Does Nietzsche's rejection of Socrates mean that he is a relativist about ethics? Can the editor of a book add citations of individual chapters to his own citation count? Yolk Urllib2.httperror: Http Error 403: Must Access Using Https Instead Of Http

I think this should definitely be posted along with setting the User-Agent as a solution to the 403 error; This happened to me on numerous sites (I think most of them python - urllib2.HTTPError: HTTP Error 403: Forbidden - Stack Overflow View More at http://stackoverflow.com/questions/13303449/urllib2-httperror-htt... python - urllib2.HTTPError: HTTP Error 403: Forbidden - Stack Overflow View More at http://stackoverflow.com/questions/13303449/urllib2-httperror-htt... http://crimsonskysoftware.com/http-error/urllib2-httperror-http-error-403-forbidden-python.html python python-2.7 urllib share|improve this question edited Nov 29 '13 at 6:47 Games Brainiac 27.1k1672124 asked Nov 29 '13 at 6:46 Anand 55211020 What do you expect the remote

Does compactness depend on the metric? Urllib.error.httperror: Http Error 403: Forbidden Human vs. This includes dynamically loading pages from another website, which may result in the website being blacklisted and permanently denied access.

What object can prove the equations?

The error has nothing to do with tweepy, it's from your custom AppAuthHandler: >>> auth = AppAuthHandler(TWITTER_CONSUMER_KEY, TWITTER_CONSUMER_SECRET) Traceback (most recent call last): File "", line 1, in raise HTTPError(req.get_full_url(), My 21-year-old adult son hates me What are the German equivalents of “First World War”, “World War I”, and “WWI”? Does anyone have an idea why this happens? Python User-agent Anyways, you can read pages like this in Python 2: req = urllib2.Request(url, headers={'User-Agent' : "Magic Browser"}) con = urllib2.urlopen( req ) print con.read() Or in Python 3: import urllib req

Given that ice is less dense than water, why doesn't it sit completely atop water (rather than slightly submerged)? http://wolfprojects.altervista.org/changeua.php share|improve this answer answered Jul 26 '10 at 16:03 Eli 80121119 add a comment| up vote 1 down vote Some websites will block access from scripts to avoid 'unnecessary' usage I think you really can't access the site, unless you are acquinted with the site creator somehow. –aIKid Nov 29 '13 at 6:58 add a comment| up vote 1 down vote http://crimsonskysoftware.com/http-error/urllib2-http-error-403-forbidden.html How strange is it (as an undergrad) to email a professor from another institution about possibly working in their lab?

What to do when majority of the students do not bother to do peer grading assignment? From Wikipedia: A web server may return a 403 Forbidden HTTP status code in response to a request from a client for a web page or resource to indicate that the Text is available under the Creative Commons Attribution-ShareAlike License; additional terms may apply. share|improve this answer answered Jul 26 '10 at 16:01 Chris Foster 8801617 2 meta.wikimedia.org/wiki/Bot_policy –Thomas Wouters Jul 26 '10 at 16:04 add a comment| up vote 1 down vote As

asked 2 years ago viewed 4722 times active 9 months ago Get the weekly newsletter! This doesn't apply to the original question, of course, but it's still useful to know. This is the page: http://en.wikipedia.org/wiki/OpenCola_(drink) This is the shell session: >>> f = urllib2.urlopen('http://en.wikipedia.org/wiki/OpenCola_(drink)') Traceback (most recent call last): File "C:\Program Files\Wing IDE 4.0\src\debug\tserver\_sandbox.py", line 1, in # Used internally If any one of have any idea about this . > > Thank You, > Spandana. > > > > > > > > -- > http://mail.python.org/mailman/listinfo/python-list > -- http://mail.python.org/mailman/listinfo/python-list

Thanks for reading.. To get the Wikipedia page titled "love": http://en.wikipedia.org/w/api.php?format=json&action=query&titles=love&prop=revisions&rvprop=content share|improve this answer answered Aug 24 '13 at 7:01 Hello World 460316 add a comment| Your Answer draft saved draft discarded Sign try: f = urllib2.urlopen('http://en.wikipedia.org/wiki/OpenCola_(drink)') except urllib2.HTTPError, e: print e.fp.read() When I print the resulting message, it includes the following "English Our servers are currently experiencing a technical problem. Internal Error--the server could not fulfill the request because of an unexpected condition You can check the return status of what its meaning.

Even a plain "Mozilla" or "Opera" is usually enough to bypass that. http://en.wikipedia.org/wiki/Wikipedia:Creating_a_bot -- Steven Previous message (by thread): urllib.error.HTTPError: HTTP Error 403: Forbidden Next message (by thread): Password hash Messages sorted by: [ date ] [ thread ] [ subject ] [ import urllib2, sys from BeautifulSoup import BeautifulSoup site= "http://en.wikipedia.org/wiki/StackOverflow" hdr = {'User-Agent': 'Mozilla/5.0'} req = urllib2.Request(site,headers=hdr) page = urllib2.urlopen(req) soup = BeautifulSoup(page) print soup The reason modified version works is because this is working for other urls.

Thank you!! Encode the alphabet cipher Why does Wikipedia list an improper pronunciation of Esperanto? June 2007. p.6.sec.3.1.

class AppAuthHandler(tweepy.auth.AuthHandler): TOKEN_URL='https://api.twitter.com/oauth2/token' def __init__(self,consumer_key,consumer_secret): token_credential = '{}:{}'.format(*map(urllib.quote, [consumer_key, consumer_secret])) credential = base64.b64encode(token_credential) value = {'grant_type': 'client_credentials'} data = urllib.urlencode(value) req = urllib2.Request(self.TOKEN_URL) req.add_header('Authorization', 'Basic {}'.format(credential)) req.add_header('Content-Type', 'application/x-www-form-urlencoded;charset=UTF-8') response=urllib2.urlopen(req, data) json_response=json.loads(response.read()) this is working for other urls. The response must include an HTTP WWW-Authenticate header to prompt the user-agent to provide credentials. What are the alternatives of compound interest for a Muslim?