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Urllib.error.httperror Http Error 404 Not Found


Solutions? For example this Error will be fatal (believe or not - it is not uncommon one when downloading urls): AttributeError: 'URLError' object has no attribute 'code' Fast, but maybe not the How to draw a clock-diagram? For a more detailed discussion of this subject - including an explanation of how Basic Authentication works - see the Basic Authentication Tutorial. check over here

python http urllib2 urllib share|improve this question edited Jul 7 '10 at 9:18 Tim Pietzcker 197k27263355 asked Jul 7 '10 at 8:25 Arnab Sen Gupta 1,61941616 Have tried the I did the following again- $ git clone https://github.com/emadshaaban92/edx-downloader $ python edx-dl.py [email protected] password Traceback (most recent call last): File "edx-dl.py", line 38, in response = urllib2.urlopen(request) File "/usr/lib/python2.7/urllib2.py", line 126, Collaborator dstftw commented Mar 21, 2016 Can you watch it in browser at all? Can the editor of a book add citations of individual chapters to his own citation count?

Urllib2 Urlopen 404

This specifies the authentication scheme and a ‘realm'. youtube-dl --verbose "https://www.youtube.com/watch\?v\=onBYsen2_eA" [debug] System config: [] [debug] User config: [] [debug] Command-line args: [u'--verbose', u'https://www.youtube.com/watch\\?v\\=onBYsen2_eA'] [debug] Encodings: locale UTF-8, fs UTF-8, out UTF-8, pref UTF-8 [debug] youtube-dl version 2016.06.25 [debug] ewnd9 commented Mar 21, 2016 python 3 is working ok import urllib.request url = 'https://www.youtube.com/' request = urllib.request.urlopen(url) print(request.read()) and, when I set python3 as the default python in the system What does this ice key do?

share|improve this answer edited Aug 6 '15 at 0:00 YPCrumble 3,59822665 answered May 19 '15 at 13:43 sonavolob 20138 add a comment| Your Answer draft saved draft discarded Sign up Why ? command to run in terminal to check this)? Urllib.error.httperror: Http Error 400: Bad Request python url http-status-code-404 urllib2 urllib share|improve this question asked Dec 22 '09 at 15:34 user236959 add a comment| 1 Answer 1 active oldest votes up vote 34 down vote That URL

Try our newsletter Sign up for our newsletter and get our top new questions delivered to your inbox (see an example). Urllib2 Httperror 404 Make sure you are using the latest version; type youtube-dl -U to update. See section 10 of RFC 2616 for a reference on all the HTTP error codes. Basic Authentication¶ To illustrate creating and installing a handler we will use the HTTPBasicAuthHandler.

With HTTP, this is often done using what's known as a POST request. Urllib Vs Urllib2 You can verify this with Firebug or Safari/Chrome's Web Inspector. –Will McCutchen Dec 22 '09 at 16:33 I have firebug and I had checked it, but I didn't see Or you can use try - except statement to see error's details. In the common case of HTML forms, the data needs to be encoded in a standard way, and then passed to the Request object as the data argument.

  1. http.server.BaseHTTPRequestHandler.responses is a useful dictionary of response codes in that shows all the response codes used by RFC 2616.
  2. Created using Sphinx 0.6.5.
  3. geturl - this returns the real URL of the page fetched.
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  8. urllib2 examples/python/try_urllib2.py from __future__ import print_function import urllib2, sys def fetch(): if len(sys.argv) != 2: print("Usage: {} URL".format(sys.argv[0])) return url = sys.argv[1] try: f = urllib2.urlopen(url) html = f.read() print(html) except

Urllib2 Httperror 404

for file upload from HTML forms - see HTML Specification, Form Submission for more details). You will want to create openers if you want to fetch URLs with specific handlers installed, for example to get an opener that handles cookies, or to get an opener that Urllib2 Urlopen 404 I took it from linuxjournal.com/article/10940?page=0,2 –Anant Gupta Mar 4 '12 at 9:39 add a comment| up vote 0 down vote Try This Instead: from urllib import urlencode from urllib2 import urlopen Urllib2 404 Exception Currently, the socket timeout is not exposed at the http.client or urllib.request levels.

Can you check it was not a transient error on YouTube or your ISP? check my blog You can recover the content of that site's 404 page like so: import urllib2 try: print urllib2.urlopen('http://www.reefgeek.com/equipment/Controllers_&_Monitors/Neptune_Systems_AquaController/Apex_Controller_&_Accessories/').read() except urllib2.HTTPError, e: print e.code print e.msg print e.headers print e.fp.read() share|improve this answer more hot questions question feed lang-py about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Toggle navigation Code Maven Login Register Exercises CMOS Categories Type keyword: Archive About Search for '{{search_term}}' {{r}} urllib vs urllib2 in Python - fetch the content of 404 or raise exception? Raise Httperror(req.get_full_url(), Code, Msg, Hdrs, Fp)

This HOWTO aims to illustrate using urllib, with enough detail about HTTP to help you through. Given a limit with notation f, how would you solve? But as soon as you encounter errors or non-trivial cases when opening HTTP URLs, you will need some understanding of the HyperText Transfer Protocol. this content I thought it might make more sense to someone copy pasting code to see the false spelled out.

File "/usr/lib/python2.7/dist-packages/youtube_dl/extractor/common.py", line 390, in _request_webpage return self._downloader.urlopen(url_or_request) File "/usr/lib/python2.7/dist-packages/youtube_dl/YoutubeDL.py", line 1950, in urlopen return self._opener.open(req, timeout=self._socket_timeout) File "/usr/lib/python2.7/urllib2.py", line 435, in open response = meth(req, response) File "/usr/lib/python2.7/urllib2.py", line 548, Python Urllib2 Example And of course MattH's answer is very similar to the truth :) share|improve this answer answered Sep 6 '12 at 20:13 oleg.foreigner 410418 add a comment| Your Answer draft saved The default handlers will handle some of these responses for you (for example, if the response is a "redirection" that requests the client fetch the document from a different URL, urllib

Update avconv to version 10-0 or newer to fix this. [debug] Invoking downloader on 'https://r7---sn-ug5onuxaxjvh-n8vz.googlevideo.com/videoplayback?mime=video%2Fmp4&key=yt6&itag=22&ipbits=0&sver=3&lmt=1458046689112654&signature=13AA167332E9E50715862938C14AFFCC16C267CB.60E23084B322E25A920E4748ABE4B678C5DAEE2C&mm=31&source=youtube&mn=sn-ug5onuxaxjvh-n8vz&ratebypass=yes&dur=69.752&mt=1458588690&mv=m&ms=au&fexp=9405984%2C9407191%2C9413142%2C9416126%2C9417828%2C9419817%2C9420452%2C9422596%2C9423661%2C9423662%2C9427902%2C9428422%2C9429160%2C9429808%2C9431012%2C9431270%2C9431400%2C9431619%2C9432057%2C9432437&ip=' [download] Destination: Unity Launcher And Dash Can Now Be Moved To The Bottom Of The Screen

Which towel will dry faster? The python library is able to retrieve the open graph tags for all other urls but this url seems to be an anomaly. See the Python tutorial. Urllib2 Download File Why was Susan treated so unkindly? "Full-time Employment is a Loophole in the Law to Make Wages Lower"?

The HTTPError instance raised will have an integer ‘code' attribute, which corresponds to the error sent by the server. If you know what the realm is (from the authentication header sent by the server), then you can use a HTTPPasswordMgr. I had, instead, the commit 620a67c , back from Date: Fri Oct 26 16:57:29 2012 +0200 I now have manually downloaded the master, and it works. have a peek at these guys probably that's HTTP error 404..but I don't know how to specify that catch only error 404 and let the system run the default handler for other events..ny suggestions??

It works well on my computer. Please enable JavaScript to view the comments powered by Disqus. Any ideas how could python's urllib2 use cached dns? How do I respond to the inevitable curiosity and protect my workplace reputation?

creating a symbolic link in linux directory How much more than my mortgage should I charge for rent? Maybe this might be the same problem encountered by @dhruvkapur91 ? What specifically about the server response is causing this?1python urllib2 basic authentication0urllib2.urlopen failing while urllib.urlopen working on same URL0Receiving 403 from Googlemaps0Inability to extract data from website using urllib24urllib2.quote does not For example, you can make an FTP request like so: req = urllib.request.Request('ftp://example.com/') In the case of HTTP, there are two extra things that Request objects allow you to do: First,

Browse other questions tagged python http urllib2 urllib or ask your own question. Other sorts of handlers you might want to can handle proxies, authentication, and other common but slightly specialised situations. Number 2¶ from urllib.request import Request, urlopen from urllib.error import URLError req = Request(someurl) try: response = urlopen(req) except URLError as e: if hasattr(e, 'reason'): print('We failed to reach a server.') Join them; it only takes a minute: Sign up catch specific HTTP error in python up vote 42 down vote favorite 9 I want to catch a specific http error and

Not the answer you're looking for? more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed It's highly likely it'll fail at some point. HTTP is based on requests and responses - the client makes requests and servers send responses.

Openers and Handlers¶ When you fetch a URL you use an opener (an instance of the perhaps confusingly-named urllib.request.OpenerDirector). Given that ice is less dense than water, why doesn't it sit completely atop water (rather than slightly submerged)?